This material prepared and compiled by Akula. Praveen Kumar, SPM, Papannapet Sub Office-502 303, Medak Division, Andhra Pradesh (9849636361, 8019549939)

Disclaimer:- All questions/Information provided in this post are Compiled by A. Praveen Kumar for in good faith of Departmental Employees. The types of questions, number of questions and standard of questions may be vary in actual examination. This is my predictions only. Author of blog does not accepts any responsibility in relation to the accuracy, completeness, usefulness or otherwise, of the contents.

                        TIME AND DISTANCE

1. Speed, Time and Distance:

Speed =		Distance		,	Time =		Distance		,	Distance = (Speed x Time).
		Time					Speed

2. km/hr to m/sec conversion:

x km/hr =		x x	5		m/sec.
			18

3. m/sec to km/hr conversion:

x m/sec =		x x	18		km/hr.
			5

4. If the ratio of the speeds of A and B is a : b, then the ratio of the

the times taken by then to cover the same distance is	1	:	1	or b : a.
	a		b

5. Suppose a man covers a certain distance at x km/hr and an equal distance at ykm/hr. Then,

the average speed during the whole journey is		2xy		km/hr.
		x + y

You have to know only two conversions when needed

1) kilometre/hour into metre/sec use 5/18 from (1000/3600)

2) metre/sec into kilometre/hour use 18/5 from (3600/1000)

Fastest multiplication and division knowledge will help you to solve time and distance easily

 For example;

1.A person crosses a 50 m long street in 5sec. What is his speed in km per hour? Here we came to know he tooks 5 sec to cross 50 metre long So, he goes 10 metre per second, here use our conversion (2)   10*18/5 2*18=36 That person crosses in the speed of 36 km/hr 2.An aeroplane covers a certain distance at a speed of 240 km/hr in 5 hours. To cover the same distance in 1 2/3 hours, it must travel at a speed of? Just listen the question ; It flies 240 kmph and it covers the distance in 5 hours So the total distance covered by aeroplane is (5*240=1200 km) In 300 min(5 hours) it covers 1200 Our question is within 1 2/3hours( 100 min) it need to cover same distance(1200 km)  what is the speed  300 min in the speed 240 km/hr 100 min in the speed? Time and distance is opposite proportion If time increases  to cover same distance speed is decreased If time decreases  to cover same distance speed is increased 300 min                                   240 km/hr 100 min(300/3)                        720 km/hr(240*3) It must travel to cover 1200 km in 1 2/3 hour is 720 km/hr

TIME AND DISTANCE SHORTCUTS

1.If a person travels half a distance in a journey at x km/hr and remaining half at the speed of y km/hr, the average speed of the whole journey is given by:

Example 1

A person travels half of journey at the speed of 30 km/hr and the next half at a speed of 15 km/hr. What is the average speed of the person during the whole journey?

Sol:

Here; x= 30 and y= 15

Putting the values we get:

Answer= 20 km/hr

Short Cut 2

If a person travels three equal distances in a journey at a speed of x km/hr, y km/hr and z km/hr. The average speed is given by:

Example 2

Ravi starts from Delhi to Agra a distance of about 300 kms. He divided his journey into a distance of thee equal parts in terms of distance and covered them with the speed of 30 km/hr, 60 km/hr and 90 km/hr, calculate his average speed during the journey:

Sol:

Here: x= 30, y= 60, z= 90.

Putting the values we get:

Answer= 49.09 km/hr

Short Cut-3

If a person travels Mth part of a distance at x km/hr, Nth part at y km/hr and the remaining Pth part at z km/hr,

Then his average speed in km/hr is given by:

If instead of proportion, the parts of the distance are given in percentage i.e. M%, N% and P% respectively, then the formula becomes:

Example 3

Hari travels 20% of a distance at an average speed of 20 km/hr, next 30% distance at an average speed of 30 km/hr and the remaining 50% of distance at the average speed of 50 km/hr. Find his average speed during the whole journey.

Sol:

Here M=20, N=30 and P= 50 also x= 20, y= 30 and z= 50

Putting the values we get:

Answer =33.33 km/hr

4If a car does a journey in 'T' hrs, the first half at 'a' km/hr and the second half at 'b' km/hr. The total distance covered by the car:

                     (2 x Time x a x b ) / (a + b).

 A motorcar does a journey in 10 hrs, the first half at 21 kmph and the second half at 24 kmph. Find the distance?
Sol: Distance = (2 x 10 x 21 x 24) / (21+24)
                      = 10080 / 45
                      = 224 km.


5.If a person goes from 'A' to 'B' at a speed of 'a' kmph and returns at a speed of 'b' kmph and takes 'T' hours in all, then the distance between the A and B:

 Total time taken x (Product of the two Speeds / Addition of the two speeds)

 A boy goes to school at a speed of 3 kmph and returns to the village at a speed of 2 kmph. If he takes 5 hrs in all, what is the distance between the village and the school?

Sol: Let the required distance be x km.
Then time taken during the first journey = x/3 hr.
and time taken during the second journey = x/2 hr.
x/3 + x/2 = 5 => (2x + 3x) / 6 = 5
=> 5x = 30.
=> x = 6
required distance = 6 km.

                                            EXAMPLES

1.An athlete runs 200 meters race in 24 seconds. His speed is:

Sol:

Speed =

200 24

m/sec =

25 3

m/sec =

25 3

x

18 5

km/hr = 30 km/hr.

2.Two trains starting at the same time from two stations 200 km apart and going in opposite directions cross each other at a distance of 110 km from one of the stations. What is the ratio of their speeds?

Sol:

In the same time, they cover 110 km and 90 km respectively.

Ratio of their speeds = 110 : 90 = 11 : 9

3.How long will a boy take to run round a square field of side 35 meters, If he runs at the rate of 9 km/hr?

Sol:

Speed = 9 km/hr = 9 x 5 18  m/sec = 5 2  m/sec.

Distance = (35 x 4) m = 140 m.

Time taken = 140 x 2 5  sec = 56 sec.

4.The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travels towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 km/hr. At what time do they meet

Sol:

Suppose they meet x hrs after 8 a.m. Then,

(Distance moved by first in x hrs) + [Distance moved by second in (x-1) hrs] = 330

60x + 75(x – 1) = 330   x  =  3

So, they meet at (8 + 3), i.e. 11 a.m.

5.A person crosses a 600 m long street in 5 minutes, What is his speed in km per hour

Sol:

Speed = 600 5 x 60  m/sec = 2 m/sec = 2 x 18 5  km/hr = 7.2 km/hr.

6.Two men start together to walk to a certain destination, one at 3 kmph and together at 3.75 kmph. The latter arrives half an hour before the former. The distance is:

Sol: Let the distance be x km. Then,

x 3 - x 3.75 = 1 2 2.5x - 2x = 3.75  x = 3.75 0.50 = 15 2   =  7.5 km

7.The ratio between the speeds of two trains is 7: 8. If the second train runs 400 kms in 4 hours, then the speed of the first train is:

Sol: Let the speeds of two trains be 7X and 8X km/hr.

Then, 8X = 400 4  = 100  X = 100 8  = 125.

Speed of first train = (7 x 12.5) km/hr = 87.5 km/hr

8.A is twice as fast as B and B is thrice as fast as C is. The journey covered by C in 54 minutes will be covered by B in:

Sol: Let C's speed = x km/hr, Then, B's speed = 3x km/hr and A's speed = 6x km/hr

Ratio of speeds of A, B, C = 6x : 3x : x = 6 : 3 : 1

Ratio of times taken = 1 6 : 1 3  : 1 = 1 : 2 : 6

If C takes 6 min., then B takes 2 min.

If C takes 54 min., then B takes 2 6  x 54  min. = 18 min.

9.A boy rides his bicycle 10 km at an average speed of 12 km/hr and again travels 12 km at an average speed of 10 km/hr. His average speed for the entire trip is approximately

Sol:

Total distance travelled = (10 + 12) km/hr = 22 km/hr

Total time taken = 10 12 + 12 10  hrs = 61 30  hrs

Average speed = 22x 30 61  km/hr = 10.8 km/hr

10. If a train runs at 40 kmph, it reaches its destination late by 11 minutes but if it runs at 50 kmph, it is late by 5 minutes only. The correct time for the train to complete its journey is:

Sol:

Let the correct time to complete the journey be x min.

Distance covered in (x + 11) min. at 40 kmph = Distance covered in (x + 5) min. at 50 kmph

(x + 11) 60  x 40 = (x + 5) 60  x 50 x = 19 min.

11. An express train traveled at an average speed of 100km/hr, stopping for minutes after every 75 km. How long did it take to reach its destination 600 km from the starting point?

Sol:

Time taken to cover 600 km = 600 100  hrs = 6 hrs

Number of stoppages = 600  - 1 = 7 75

Total time of stoppage = (3 x 7) min = 21 min.

Hence, total time taken = 6 hrs 21 min.

12.Top of Form

Bottom of Form

Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?

Sol:

Due to stoppages, it covers 9 km less.

Time taken to cover 9 km  = 9 54  x 60  min  =  10 min.

13.Three persons are walking from a place A to another place B. Their speeds are in the ratio of 4 : 3 : 5. The time ratio to reach B by these persons will be :

Sol: Ratio of speeds = 4 : 3 : 5

Ratio of times taken = 1 4 : 1 3 : 1 5   =  15 : 20 : 12

14. Walking ¾ of his speed, a person is 10 min late to his office. Find his usual time to cover the distance?

Sol:  Usual time = Late time / {1/ (3/4) - 1)
= 10 / (4/3 -1)
= 10 / (1/3)
= 30 minutes.

15. Running 4/3 of his usual speed, a person improves his timing by 10 minutes. Find his usual timing by 10 minutes. Find his usual time to cover the distance?

Sol:  Usual time = Improved time / {1 - (1/ (3/4)}
= 10 / { 1- (3/4) }
= 40 minutes.

16. A train travelling 25 kmph leaves Delhi at 9 a.m. and another train travelling 35 kmph starts at 2 p.m. in the same direction. How many km from will they be together?

Sol: Meeting point's distance from the starting point = [25 x 35 x (2p.m. - 9 a.m)] / (35 -25)
= (25 x 35x 5) / 10
= 4375 / 10
= 437.5 km .

17. A motor car starts with the speed of 70 km/hr with its speed increasing every two hours by 10 kmph. In how many hours will it cover 345 kms?

Sol:

Distance covered in first 2 hours = (70 x 2) km = 140 km

Distance covered in next 2 hours = (80 x 2) km = 160 km

Remaining distance = 345 – (140 + 160) = 45 km.

Speed in the fifth hour = 90 km/hr

Time taken to cover 45 km = 45 90  hr = 1 2  hr

Total time taken = 2 + 2 + 1 2  = 4 1 2  hrs

18.A person travels from P to Q at a speed of 40 kmph and returns by increasing his speed by 50%. What is his average speed for the both the trips?

Sol:

Speed on return trip = 150% of 40 = 60 kmph.

Average speed = 2 x 40 x 60 40 + 60  km/hr = 4800 100  km/hr = 48 km/hr.

19.A man takes 5 hours 45 min. in walking to a certain place and riding back. He would have gained 2 hours by riding both ways. The time he would take to walk both ways, is:

Sol:

Let the distance be x km. Then,

(Time taken to walk x km) + (Time taken to ride x km) = 23 4  hrs

(Time taken to walk 2x km) + (Time taken to ride 2x km) = 23 2  hrs

But, time taken to ride 2x km = 15 4  hrs

Time taken to walk 2x km = 23 2 - 15 4  hrs = 31 4  hrs = 7 hrs 45 min.

20. A can complete a journey in 19 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.

Sol: Let the total distance be X km. Then,

1  x 2 21 + 1  x 2 24 = 10 x 21 + x 24 = 20

15x = 168 x 20  x = 168 x 20 15  = 224 km.

21.A man in a train notices that he can count 21 telephone posts in one minute. If they are known to be 50 meters apart, then at what speed is the train travelling?

Sol: Number of gaps between 21 telephone posts = 20

Distance traveled in 1 minute = (50 x 20) m = 1000 m = 1 km

Speed = 60 km/hr

22. Mary jogs 9 km at speed of 6 km per hour. At what speed would she need to jog during the next 1.5 hours to have an average of 9 km per hour for the entire jogging session?

Sol: Let speed of jogging be x km/hr

Total time taken = 9 6  hrs + 1.5 hrs  = 3 hrs.

Total distance covered = (9 + 1.5x) km

9 + 1.5x 3  = 9 9 + 1.5x = 27 3 2 x = 18 x = 18 x 2 3  = 12 kmph

23. A train covers a distance of 10 km in 12 minutes. If its speed is decreased by 5 km / hr, the time taken by it to cover the same distance will be:

Sol:

Speed = 10 x 60 12  km / hr = 50 km / hr

New speed = (50 – 5) km / hr = 45 km / hr

Time taken = 10 45  hr = 2 9  x 60  min = 13 1 3   min = 13 min 20 sec.

24.In covering a certain distance, the speeds of A and B are in the ratio of 3 : 4. A takes 30 minutes more than B to reach the destination. The time taken by A to reach the destination is:

Sol:

Ratio of speeds  =  3 : 4. Ratio of times taken  =  4 : 3.

Suppose A takes 4x hrs and B takes 3x hrs to reach the destination. Then,

4x - 3x  = 30 60 = 1 2   or   x = 1 2

Time taken by A = 4x hrs  = 4 x 1 2  hrs = 2 hrs

25.A person has to cover a distance of 6 km in 45 minutes. If he covers one-half of the distance in two-thirds of the total time, to cover the remaining distance in the remaining time, his speed (in km/hr) must be:

Sol:

Remaining distance = 3 km and Remaining time = 1 3  x 45  min = 15 min = 1 4  hour

Required speed = (3 x 4) km/hr = 12 km/hr